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We can inculcate a sense of humor and curiosity in the young miinds by showing novel ideas and concepts. Incidentally even at an early age the student will develop a sort of fascination for numbers and he will find enjoyment, amusement and recreation in solving problems. Is not what every parent's dream? The student will develop positive initerest in mathematics which will stay with him for the rest of his life. Instead of coming out of the class with tears in their eyes, there will be all smiles. Mathematics will be a fun class. This goal can be achieved through recreational methods of teaching mathematics.

Nepier Multiplications

Any number of digits multiplications can be done by using this system While taking the products corresponding to the first row and the last column, we write tens value on the upper side of the diagonal and write the units place in the lower side of the diagonal. Without using the logarithms we can do bigger mutiliplications also with this system.

Step 1: From the first row and the last column choose the corresponding squares and write them side by side
Step 2: Add the digits diagonally from right to left from bottom.
Example 1: For 23 x 45
Units = 5
Tens = 0 + 1 + 2 =3
Hundreds = 1 + 8 + 1 = 10, carry 1.
Thousands = 1 + 0 = 1
Hence 23 x 45 = 1035
   
Example 2: For 698 x 47
Units = 6
Tens = 3 + 5 + 2 = 10, carry 1
Hundreds = 1 + 2 + 6 + 6 = 18, carry 1
Thousands = 1 + 4 + 4 + 3 = 12
Hence 698 x 47 = 32806
   
Example 3: For 786 x 594
Units = 4
Tens = 2 + 2 + 4 = 8
Hundreds = 8 + 3 + 2 + 5 + 0 = 18, carry 1
Thousands = 1 + 2 + 3 + 7 + 3 = 16, carry 1
Hundred Thousands = 1 + 3 = 4
Hence 786 x 594 = 466,884
   
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Multiplications with twice of the numbers

If we know how to twice the numbers, we can find the products without doing multiplications

Step 1: Write the twice of the numbers starting from 1 on the left side
Step 2: Write the twice of the multiplier on the right side
  Example 1: For 16 x 48
 
1   48
2   96
4   192
8   384
16 768

Hence 16 x 48 = 768
  Example 2: For 35 x 56
 
1   56
2   112
4   224
8   448
16   896
32 1792


Since 35 = 32 + 2 + 1, add the numbers opposite to 32, 2 and 1 and take it as the number.

Hence 35 x 56 = 1792 + 112 + 56 = 1960

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Multiplications with half and twice of the numbers

If we know how to write half of the numbers and how to write twice of the numbers we can do all multiplications.

Step 1: Write the multiplicand on the left side and the multiplier on the right side
Step 2: Take half of the left hand numbers till you arrive at 1, leaving the remainders if any
Step 3: Take the twice of the right hand numbers and write them opposite to the left hand numbers
Step 4: Add the numbers opposite to the odd numbers of the left hand side and take it as the answer
  Example 1: For 16 x 18
 
16   18
8   36
4   72
2   144
1 288

On the left side odd number is 1.

Hence 16 x 18 = 288

  Example 2: For 24 x 52
 
24   52
12   104
6   208
3   416
1 832


On the left side odd number are 1 and 3.

Hence 24 x 52 = 416 + 832 = 1248

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Multiplications with the reverse of the second number
  Product of two digit numbers
Step 1: Write the multiplicand at three different places as shown below
Step 2: Write the multiplier in the reverse order on a pience of paper and place it below the first number as shown below at three stages
Step 3: Find the products of the opposite numbers and find the sum
 

Example 1: For 21 x 32

 

Write 32 as 23 on a piece of paper and place it below the first number as shown below.

  2 1
  x  
2 3  
  6  
2 1
x x
2 3
4 + 3 = 11
2 1  
  x  
  2 3
  2  

Hence 21 x 32 = 672

 

EXAMPLE 2: For 321 x 321

 
  4 1
  x  
1 4  
  16  
4 1
x x
1 4
4 + 4 = 8
4 1  
  x  
  1 4
  1  

Hence 41 x 41 = 1681

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Product of three digit numbers
Step 1: Write the multiplicand at five different places as shown below
Step 2: Write the multiplier in the reverse order on a piece of paper and place it below the first number as shown below at five stages
Step 3: Find the products of the opposite numbers and find the sum

EXAMPLE 1: For 432 x 123

     

Write 123 as 321 on a piece of paper and place it below the first number as shown below.

    4 3 2
    x    
3 2 1    
    4    
  4 3 2  
  x x    
3 2 1    
8 + 3 = 11
  4 3 2  
  x x x  
  3 2 1  
12 + 6 + 2 = 20
  4 3 2  
    x x  
    3 2 1
9 + 4 = 13
4 3 2    
    x    
    3 2 1
    6    

Hence 432 x 123 = 4 / 11 / 20 / 13 / 6 = 53136

EXAMPLE 2: For 321 x 321

     
    3 2 1
    x    
1 2 3    
    9    
  3 2 1  
  x x    
1 2 3    
6 + 6 = 12
  3 2 1  
  x x x  
  1 2 3  
3 + 4 + 3 = 10
  3 2 1  
    x x  
    1 2 3
2 + 2 = 4
3 2 1    
    x    
    1 2 3
    1    

Hence 321 x 321 = 9 / 12 / 10 / 4 / 1 = 103,041

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